2j^2-5j-12=0

Solution for 2j^2-5j-12=0 equation:

Simplifying
2j2 + -5j + -12 = 0

Reorder the terms:
-12 + -5j + 2j2 = 0

Solving
-12 + -5j + 2j2 = 0

Solving for variable 'j'.

Factor a trinomial.
(-3 + -2j)(4 + -1j) = 0

Subproblem 1
Set the factor '(-3 + -2j)' equal to zero and attempt to solve:

Simplifying
-3 + -2j = 0

Solving
-3 + -2j = 0

Move all terms containing j to the left, all other terms to the right.

Add '3' to each side of the equation.
-3 + 3 + -2j = 0 + 3

Combine like terms: -3 + 3 = 0
0 + -2j = 0 + 3
-2j = 0 + 3

Combine like terms: 0 + 3 = 3
-2j = 3

Divide each side by '-2'.
j = -1.5

Simplifying
j = -1.5
Subproblem 2
Set the factor '(4 + -1j)' equal to zero and attempt to solve:

Simplifying
4 + -1j = 0

Solving
4 + -1j = 0

Move all terms containing j to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + -1j = 0 + -4

Combine like terms: 4 + -4 = 0
0 + -1j = 0 + -4
-1j = 0 + -4

Combine like terms: 0 + -4 = -4
-1j = -4

Divide each side by '-1'.
j = 4

Simplifying
j = 4
Solution
j = {-1.5, 4}